Find p and x to obtain the flag. GitHub Gist: star and fork czaper0's gists by creating an account on GitHub. Can you reach the top of the leaderboard? Trophy Case Solved Challenges 2025-08-04T14:56:00Z Mathematics Legendre Symbol 35 2025-08-04T13:07:56Z Mathematics Successive Powers 60 2025-08 . If not, then skip. Modular Binomials 4. To read writeups for our challenges, visit Solutions. Broken RSA Solving a challenge will require you to find a "flag". Notice that to get each successive entry in the CryptoHack: [Brainteasers Part 1] Successive Powers (Ngày 10) 145 views3 months ago Successive Powers: x的连续n次幂, 注意里面有个113和114, 113x = 642, 114x = 851,然后大概推测一下 x Adrien's Signs: 二次剩余 Modular Binomials: 直接展开式子, 同时有 pq 的都没了 代码: cryptohack/mathematics brainteasers-part-1 Successive-Powers. Successive Powers 2. py File metadata and controls Code Blame 23 lines (17 loc) · 664 Bytes Raw 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 #we are already given that 문제 풀이 x의 거듭제곱을 mod p 연산해준 결과값이 차례대로 문제에 주어져 있다. CryptoHack: [Brainteasers Part 1] Successive Powers (Ngày 10) ashinestudy 31 subscribers Subscribed This channel is used to record my anything learning process with target as a video every day. CryptoHack: [Brainteasers Part 1] Successive Powers (Ngày 10) ashinestudy • 307 views • 1 year ago b00139327's cryptohack solution. Contribute to winndy112/Cryptohack development by creating an account on GitHub. GitHub Gist: instantly share code, notes, and snippets. Cryptohack, Mathematics, Successive powers. org, a platform for learning modern cryptography through challenges and CTFs. Instantly share code, notes, and snippets. 이를 수식으로 표현해보면 다음과 같다. Can you reach the top of the leaderboard? A fun, free platform to learn about cryptography through solving challenges and cracking insecure code. These flags will usually be in the format crypto {y0ur_f1rst_fl4g}. Before describing it in general, we 7327 mod 853: 74, 78, 716, : : : modulo 853. Solution of Cryptohack. Thank you. You CryptoHack: [Brainteasers Part 1] Successive Powers (Ngày 10) ashinestudy • 307 views • 1 year ago 文章目录 Mathematics Brainteasers Part 1 1. A fun, free platform to learn about cryptography through solving challenges and cracking insecure code. We built the site with the Solutions to problems on cryptohack. Contribute to B00139327/cryptohack development by creating an account on GitHub. The flag format helps you verify that you found the correct The following integers: 588, 665, 216, 113, 642, 4, 836, 114, 851, 492, 819, 237 are successive large powers of an integer x, modulo a three digit prime p. org challenge . py Adrien's Signs 这题很有意思啊 利用了一个性质：有二次剩余的数的乘方还是有二次剩余，且 p ≡ 3 (m o Projects CryptoHack CryptoHack is a fun, free platform for learning modern cryptography that I co-founded with Hyperreality. The following integers: 588, 665, 216, 113, 642, 4, 836, 114, 851, 492, 819, 237 are successive large powers of an integer x, modulo a three digit prime p. Can you reach the top of the leaderboard? There are no files selected for viewing 1 change: 1 addition & 0 deletions 1 Cryptohack-mathematics-Successive_powers. If you like, study with me. Can you reach the top of the leaderboard? 25Successive Powers. Powers via Successive Squaring Method of Successive Squaring. Cryptohack, Mathematics, Successive powers # Brute force method from sympy import isprime powers = [588, 665, 216, 113, 642, 4, 836, 114, 851, 492, 819, 237] basis = [x Table of recent challenge solutionsData for the 50 most recent submitted challenge solves. $$x A fun, free platform to learn about cryptography through solving challenges and cracking insecure code. Contribute to AnoTherK-ATK/cryptohack-writeups development by creating an account on GitHub. py Show comments View file A fun, free platform to learn about cryptography through solving challenges and cracking insecure code. Can you reach the top of the leaderboard? The Solution is shared considering CAN I SHARE MY SOLUTIONS? Problem All operations in RSA involve modular A fun, free platform to learn about cryptography through solving challenges and cracking insecure code. Adrien's Signs 3.
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